Hint: The General Store

The puzzle could be solved just like the "Torn Number" - Problem, but there is something that could be of assistance in finding solutions:

The propagation might have use for some information about addition, for example, that in

    A B C
 +  D E F
 ________
  G H I J
I, for instance, is B plus E plus the Carry from C and F - so,
J = (C + F) mod 10, 
and
I = (B + E + (C + F) div 10) mod 10, 
and so forth. Certainly, in summing up two figures the carry cannot exceed one. It is straightforward to see how high it can be for two figures...

Try to incorporate these additional constraints... but don't be surprised if at first glance they don't yield an improvement!


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