10 Mar 2004
CS 3243 - Uncertainty
6
An Example
n(due to MIT’s open coursework slides)
n
0
1
1
0
1
0
1
0
1
1
0
0
0
0
1
0
1
0
1
1
0
1
0
0
1
1
0
0
0
0
1
1
1
0
0
1
0
1
0
1
1
1
1
0
0
1
0
1
1
0
y
f4
f3
f2
f1
R1(1,1) = 1/5: fraction of all positive examples that have feature 1 = 1
R1(0,1) = 4/5: fraction of all positive examples that have feature 1 = 0
R1(1,0) = 5/5: fraction of all negative examples that have feature 1 = 1
R1(0,0) = 0/5: fraction of all negative examples that have feature 1 = 0
Continue calculation of R2(1,0) …